Two transparent media A and B are separated b | vedclass

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(A) The refractive index $\mu$ is inversely proportional to the speed of light $v$ in a medium,given by $\mu = \frac{c}{v}$,where $c$ is the speed of

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$\sin^{-1}(0.750)$

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(A) The refractive index $\mu$ is inversely proportional to the speed of light $v$ in a medium,given by $\mu = \frac{c}{v}$,where $c$ is the speed of light in vacuum.The critical angle $i_c$ for light traveling from a denser medium to a rarer medium is given by the formula $\sin i_c = \frac{\mu_R}{\mu_D}$,where $\mu_R$ is the refractive index of the rarer medium and $\mu_D$ is the refractive index of the denser medium.Since $\mu \propto \frac{1}{v}$,we have $\frac{\mu_R}{\mu_D} = \frac{v_D}{v_R}$.Given $v_A = 1.5 	imes 10^8 \ m/s$ and $v_B = 2.0 	imes 10^8 \ m/s$,medium $A$ is the denser medium $(D)$ and medium $B$ is the rarer medium $(R)$.Therefore,$\sin i_c = \frac{v_A}{v_B} = \frac{1.5 	imes 10^8}{2.0 	imes 10^8} = \frac{1.5}{2.0} = \frac{3}{4} = 0.750$.Thus,$i_c = \sin^{-1}(0.750)$.

Two transparent media $A$ and $B$ are separated by a plane boundary. The speed of light in those media are $1.5 \times 10^{8} \ m/s$ and $2.0 \times 10^{8} \ m/s$,respectively. The critical angle for a ray of light for these two media is:

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