Two vertical poles $AB = 15 \ m$ and $CD = 10 \ m$ are standing apart on a horizontal ground with points $A$ and $C$ on the ground. If $P$ is the point of intersection of $BC$ and $AD$,then the height of $P$ (in $m$) above the line $AC$ is:

  • A
    $\frac{20}{3}$
  • B
    $5$
  • C
    $\frac{10}{3}$
  • D
    $6$

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