Using mathematical induction,the numbers $a_n$ are defined by:
$a_0 = 1, a_{n+1} = 3n^2 + n + a_n, (n \geq 0)$.
Then,$a_n$ is equal to:

  • A
    $n^3 + n^2 + 1$
  • B
    $n^3 - n^2 + 1$
  • C
    $n^3 - n^2$
  • D
    $n^3 + n^2$

Explore More

Similar Questions

Prove that for all $n \in N$,$41^{n}-14^{n}$ is a multiple of $27$ using the principle of mathematical induction.

Difficult
View Solution

Use the Principle of Mathematical Induction to show that for a sequence $d_{1}, d_{2}, d_{3}, \ldots$ defined by $d_{1}=2$ and $d_{k}=\frac{d_{k-1}}{k}$ for all $k \geq 2$,the general term is $d_{n}=\frac{2}{n!}$ for all $n \in N$.

Difficult
View Solution

Prove that the following is true for all $n \in N$ using the principle of mathematical induction:
$10^{2n-1} + 1$ is divisible by $11$.

Difficult
View Solution

Let $P(n) = 3^{2n+1} + 2^{n+2}$ where $n \in N$. Then

For all $n \in \mathbb{N}$,if $1^2+2^2+3^2+\ldots+n^2 > x$,then $x=$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo