Verify whether the following is True or False:
$-3$ is a zero of $y^{2}+y-6$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(TRUE) zero of a polynomial $p(y)$ is a value $c$ such that $p(c) = 0$.
Let $p(y) = y^{2} + y - 6$.
Substitute $y = -3$ into the polynomial:
$p(-3) = (-3)^{2} + (-3) - 6$
$p(-3) = 9 - 3 - 6$
$p(-3) = 0$.
Since $p(-3) = 0$,it is True that $-3$ is a zero of the polynomial $y^{2} + y - 6$.

Explore More

Similar Questions

Check whether $p(x)$ is a multiple of $g(x)$ or not:
$p(x) = 2x^3 - 11x^2 - 4x + 5, \quad g(x) = 2x + 1$

Divide $p(x)=21+10 x+x^{2}$ by $g(x)=2+x$ and find the quotient and the remainder.

Degree of the polynomial $4 x^{4}+0 x^{3}+0 x^{5}+5 x+7$ is

Factorise $9x^{2} + 42x + 49$.

Write the following cube in expanded form: $(3a + 5b)^3$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo