Water drops fall at regular intervals from a tap which is $5\,m$ above the ground. The third drop is leaving the tap at the instant the first drop touches the ground. How far above the ground is the second drop at that instant?

$A$ balloon starts rising from the ground with an acceleration of $1.25\, m/s^2$. After $8\,s$,a stone is released from the balloon. The stone will $(g = 10\, m/s^2)$:

$A$ stone falls from a balloon that is descending at a uniform rate of $12 \, m/s$. The displacement of the stone from the point of release after $10 \, s$ is.......$m$ $(g = 9.8 \, m/s^2)$

$A$ ball is thrown vertically downward with a velocity of $20\; m/s$ from the top of a tower. It hits the ground after some time with a velocity of $80\; m/s$. The height of the tower is $......m$ : $(g = 10\; m/s^2)$

$A$ ball is thrown vertically upwards with an initial velocity $u$ and reaches its maximum height in $5 \,s$. The ratio of the distance travelled by the ball in the $2^{nd}$ and $7^{th}$ second is (assume $g=10 \,m/s^2$):

$A$ stone is dropped from the top of a tower of height $h = 60 \ m$. Simultaneously,another stone is projected vertically upwards from the foot of the tower. They meet at a height $\frac{2h}{3}$ from the ground level. Find the initial velocity of the stone projected upwards. (Take $g = 10 \ ms^{-2}$) (in $ms^{-1}$)