We have three aqueous solutions of NaCl label | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The Van't Hoff factor $(i)$ for a strong electrolyte like $NaCl$ is given by the formula $i = 1 + (n-1)\alpha$,where $n$ is the number of ions pro

Vedclass · Accepted Answer

$i_{A} < i_{B} < i_{C}$

Vedclass · Answer

(C) The Van't Hoff factor $(i)$ for a strong electrolyte like $NaCl$ is given by the formula $i = 1 + (n-1)\alpha$,where $n$ is the number of ions produced per formula unit and $\alpha$ is the degree of dissociation.For $NaCl$,$n = 2$. As the concentration of the solution decreases,the degree of dissociation $(\alpha)$ increases due to the decrease in inter-ionic attractions.Therefore,as concentration decreases from $0.1 \ M$ to $0.001 \ M$,$\alpha$ increases,which leads to an increase in the value of $i$.Thus,the order of the Van't Hoff factor is $i_{A} < i_{B} < i_{C}$.

We have three aqueous solutions of $NaCl$ labelled as '$A$','$B$' and '$C$' with concentrations $0.1 \ M$,$0.01 \ M$,and $0.001 \ M$ respectively. The value of the Van't Hoff factor for these solutions will be in the order . . . . . . .

Similar Questions

Which of the following aqueous solutions exhibits the minimum freezing point depression upon complete dissociation?

Calculate the approximate $\Delta T_b$ (in $K$) for $0.001 \ m$ $KCl$ solution, if its van't-Hoff factor is $1.98$ [$K_b$ of water is $0.52 \ K \ kg \ mol^{-1}$].

Which of the following solutions in water possesses the lowest vapour pressure?

Which of the following solutions will have the highest boiling point?

Vedclass Test Series

Exam Paper Generator

Online Exam Module