What are $X, Y, Z$ in the following reaction sequence?
$CH_3-CH=CH-CH_3$ $\xrightarrow{X} CH_3COOH$ $\xrightarrow{Y} CH_3COCl$ $\xrightarrow[\text{Anhy. } AlCl_3]{\text{Benzene}} Z$

  • A
    $KMnO_4 / H^{+} ; SOCl_2 ;$ Acetophenone
  • B
    $KMnO_4 / H^{+} ; Cl_2 ;$ Propiophenone
  • C
    Cold $KMnO_4 ; SOCl_2 ;$ Propiophenone
  • D
    Cold $KMnO_4 ; Cl_2 ;$ Acetophenone

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Similar Questions

Which of the following is the correct order of decarboxylation of $\beta$-keto carboxylate anion?

The acidity of compounds $I-IV$ in water follows the order:
$I.$ ethanol
$II.$ acetic acid
$III.$ phenol
$IV.$ acetonitrile

Assertion: Acetamide has a more polar $C=O$ group than ethyl acetoacetate.
Reason: $-\ddot{N}H_{2}$ is more electron-donating than $-\ddot{O}C_{2}H_{5}$.

The reagent$(s)$ required for the following conversion are:

How will you bring about the following conversions in not more than two steps?
$(i)$ Propanone to Propene
$(ii)$ Benzoic acid to Benzaldehyde
$(iii)$ Ethanol to $3-$Hydroxybutanal
$(iv)$ Benzene to $m-$Nitroacetophenone
$(v)$ Benzaldehyde to Benzophenone
$(vi)$ Bromobenzene to $1-$Phenylethanol
$(vii)$ Benzaldehyde to $3-$Phenylpropan$-1-$ol
$(viii)$ Benzaldehyde to $\alpha-$Hydroxyphenylacetic acid
$(ix)$ Benzoic acid to $m-$Nitrobenzyl alcohol

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