What are X and Y respectively in the followin | vedclass

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(C) The starting material is $3$-bromobenzoic acid.$1$. Formation of $X$:Reaction with $B_2H_6$ followed by $H_3O^+$ is a selective reduction of the c

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(C) The starting material is $3$-bromobenzoic acid.$1$. Formation of $X$:Reaction with $B_2H_6$ followed by $H_3O^+$ is a selective reduction of the carboxylic acid group $(-COOH)$ to a primary alcohol $(-CH_2OH)$ without affecting the bromine $(-Br)$ substituent on the benzene ring. Thus,$X$ is $3$-bromobenzyl alcohol.$2$. Formation of $Y$:$(i)$ Esterification: $3$-bromobenzoic acid reacts with $C_2H_5OH/H^+$ to form ethyl $3$-bromobenzoate.(ii) Reduction: $DIBAL-H$ is a selective reducing agent that reduces esters $(-COOC_2H_5)$ to aldehydes $(-CHO)$.(iii) Hydrolysis: The final step yields $3$-bromobenzaldehyde as $Y$.Therefore,$X$ is $3$-bromobenzyl alcohol and $Y$ is $3$-bromobenzaldehyde. The correct option is $C$.

What are $X$ and $Y$ respectively in the following set of reactions?

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