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(C) Aldol condensation occurs in aldehydes or ketones that possess at least one $\alpha$-hydrogen atom.$1$. Methanal $(HCHO)$ has no $\alpha$-carbon,h

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$2$-methyl pentanal

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(C) Aldol condensation occurs in aldehydes or ketones that possess at least one $\alpha$-hydrogen atom.$1$. Methanal $(HCHO)$ has no $\alpha$-carbon,hence no $\alpha$-hydrogen.$2$. Butan-$1$-ol is an alcohol,not an aldehyde or ketone.$3$. $2$-methyl pentanal $(CH_3CH_2CH_2CH(CH_3)CHO)$ has one $\alpha$-hydrogen atom at the $C-2$ position,so it undergoes aldol condensation.$4$. $2,2$-dimethyl pentanal $(CH_3CH_2CH_2C(CH_3)_2CHO)$ has no $\alpha$-hydrogen atom because the $C-2$ carbon is fully substituted with two methyl groups and the aldehyde group.Therefore,the correct option is $C$.

Which of the following compounds would undergo aldol condensation?

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