What are X and Y respectively in the followin | vedclass

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(D) $C_2D_2$ is deuteroacetylene and $CD_4$ is deuteromethane. These compounds are prepared by the deuterolysis of specific carbides.$CaC_2$ is a calc

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$CaC_2, Al_4C_3$

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(D) $C_2D_2$ is deuteroacetylene and $CD_4$ is deuteromethane. These compounds are prepared by the deuterolysis of specific carbides.$CaC_2$ is a calcium acetylide which reacts with $D_2O$ to produce $C_2D_2$ (deuteroacetylene).$CaC_2 + 2D_2O \rightarrow C_2D_2 + Ca(OD)_2$$Al_4C_3$ is an aluminum methanide which reacts with $D_2O$ to produce $CD_4$ (deuteromethane).$Al_4C_3 + 12D_2O \rightarrow 3CD_4 + 4Al(OD)_3$Thus,$X = CaC_2$ and $Y = Al_4C_3$.

What are $X$ and $Y$ respectively in the following reactions?
$X + 2D_2O \rightarrow C_2D_2 + P$
$Y + 12D_2O \rightarrow 3CD_4 + Q$

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What are $X$ and $Y$ respectively in the following reactions?$X + 2D_2O \rightarrow C_2D_2 + P$$Y + 12D_2O \rightarrow 3CD_4 + Q$