What is A in the following reaction?C_6H_5-CH | vedclass

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(D) The reaction is the electrophilic addition of $HCl$ to allylbenzene $(C_6H_5-CH_2-CH=CH_2)$.According to Markovnikov's rule,the electrophile $(H^+

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(D) The reaction is the electrophilic addition of $HCl$ to allylbenzene $(C_6H_5-CH_2-CH=CH_2)$.According to Markovnikov's rule,the electrophile $(H^+)$ adds to the carbon atom of the double bond that has more hydrogen atoms.In allylbenzene,the double bond is between $C_2$ and $C_3$ (where $C_1$ is attached to the phenyl ring: $C_6H_5-CH_2-CH=CH_2$).$H^+$ adds to the terminal $CH_2$ group,forming a stable benzylic carbocation intermediate $(C_6H_5-CH_2-CH^+-CH_3)$.Then,the nucleophile $(Cl^-)$ attacks this carbocation to form the final product: $C_6H_5-CH_2-CHCl-CH_3$ ($1$-phenyl$-2-$chloropropane).Therefore,the correct option is $D$.

What is $A$ in the following reaction?
$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow A$

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What is $A$ in the following reaction?$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow A$