What is the R.Q. of the given reaction?2(C_{5 | vedclass

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(A) The Respiratory Quotient $(R.Q.)$ is defined as the ratio of the volume of $CO_2$ evolved to the volume of $O_2$ consumed during respiration.Formu

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$0.7$

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(A) The Respiratory Quotient $(R.Q.)$ is defined as the ratio of the volume of $CO_2$ evolved to the volume of $O_2$ consumed during respiration.Formula: $R.Q. = \frac{	ext{Volume of } CO_2 	ext{ evolved}}{	ext{Volume of } O_2 	ext{ consumed}}$From the given chemical equation: $2(C_{51}H_{98}O_6) + 145 O_2 ightarrow 102 CO_2 + 98 H_2O + 	ext{energy}$Volume of $CO_2$ evolved = $102$Volume of $O_2$ consumed = $145$$R.Q. = \frac{102}{145} \approx 0.703$Therefore, the $R.Q.$ is approximately $0.7$, which is characteristic of fats (triolein).

What is the $R.Q.$ of the given reaction?
$2(C_{51}H_{98}O_6) + 145 O_2 \rightarrow 102 CO_2 + 98 H_2O + \text{energy}$

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What is the $R.Q.$ of the given reaction?$2(C_{51}H_{98}O_6) + 145 O_2 \rightarrow 102 CO_2 + 98 H_2O + \text{energy}$