What is displacement? Explain its general meaning by giving examples.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Displacement: The distance of an oscillator (a body performing simple harmonic motion) at any instant from its equilibrium (fixed or reference) position is called the displacement of the oscillator at that instant.
The displacement is considered positive on one side of the equilibrium point and negative on the other side. In short,displacement can have zero,positive,or negative values.
Displacement refers to the change with time of any physical property under consideration. Its examples are as follows:
$(1)$ In the case of rectilinear motion of a steel ball on a surface,the distance from the starting point as a function of time is its position displacement. The choice of origin is a matter of convenience.
$(2)$ Consider a block of mass $m$ attached to a spring,the other end of which is fixed to a rigid wall,as shown in figure $(a)$. The block moves on a frictionless surface. The motion of the block can be described in terms of its distance or displacement $x$ from the wall.

Explore More

Similar Questions

$A$ particle of mass $m$ is released from rest and follows a parabolic path as shown. Assuming that the displacement of the mass from the origin is small,which graph correctly depicts the position of the particle as a function of time $?$

What is oscillatory motion? Give its examples.

$A$ simple harmonic motion is represented by $\alpha \frac{d^2 x}{d t^2}+\beta x=0$. Its period is

$A$ particle of mass $0.1 \ kg$ is executing simple harmonic motion of amplitude $0.1 \ m$. When the particle passes through the mean position,its kinetic energy is $8 \times 10^{-3} \ J$. If the initial phase is $45^{\circ}$,the equation of its motion is (Assume $x(t)$ as the position of the particle at time $t$)

$A$ particle of mass $4 \text{ mg}$ is executing simple harmonic motion along the $x$-axis with an angular frequency of $40 \text{ rad s}^{-1}$. If the potential energy of the particle is $V(x) = a + bx^2$, where $V(x)$ is in joule and $x$ is in metre, then the value of $b$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo