What is the ratio of the surface energy of 1 | vedclass

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(D) The volume of the liquid remains constant,meaning the volume of $1000$ small drops is equal to the volume of one large drop.$n \cdot \frac{4}{3} \

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$1:100$

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(D) The volume of the liquid remains constant,meaning the volume of $1000$ small drops is equal to the volume of one large drop.$n \cdot \frac{4}{3} \pi r^3 = \frac{4}{3} \pi R^3$$1000 r^3 = R^3 \implies R = 10r$Therefore,the ratio of radii is $\frac{r}{R} = \frac{1}{10}$.The surface energy $E$ is given by $E = T \cdot A$,where $T$ is surface tension and $A$ is the surface area.$\frac{E_{	ext{small}}}{E_{	ext{large}}} = \frac{4 \pi r^2 T}{4 \pi R^2 T} = \left( \frac{r}{R} ight)^2$Substituting the ratio: $\left( \frac{1}{10} ight)^2 = \frac{1}{100}$.Thus,the ratio is $1:100$.

What is the ratio of the surface energy of $1$ small drop to $1$ large drop,if $1000$ small drops combine to form $1$ large drop?

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