What is the H.C.F. of frac{4}{9}, frac{10}{21 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To find the $H.C.F.$ of fractions,we use the formula:$H.C.F. = \frac{H.C.F. 	ext{ of numerators}}{L.C.M. 	ext{ of denominators}}$Given fractions

Vedclass · Accepted Answer

$\frac{2}{63}$

Vedclass · Answer

(C) To find the $H.C.F.$ of fractions,we use the formula:$H.C.F. = \frac{H.C.F. 	ext{ of numerators}}{L.C.M. 	ext{ of denominators}}$Given fractions: $\frac{4}{9}, \frac{10}{21}, \frac{20}{63}$Step $1$: Find the $H.C.F.$ of the numerators $(4, 10, 20)$:Factors of $4 = 2 	imes 2$Factors of $10 = 2 	imes 5$Factors of $20 = 2 	imes 2 	imes 5$The common factor is $2$. So,$H.C.F. = 2$.Step $2$: Find the $L.C.M.$ of the denominators $(9, 21, 63)$:$9 = 3^2$$21 = 3 	imes 7$$63 = 3^2 	imes 7$$L.C.M. = 3^2 	imes 7 = 9 	imes 7 = 63$.Step $3$: Combine the results:$H.C.F. = \frac{2}{63}$.

What is the $H.C.F.$ of $\frac{4}{9}, \frac{10}{21}$ and $\frac{20}{63}$?

Similar Questions

Find the greatest number that will divide $390, 495,$ and $300$ without leaving a remainder.

$M$ is the largest $4$-digit number which,when divided by $4, 5, 6,$ and $7,$ leaves remainders $2, 3, 4,$ and $5$ respectively. What is the remainder when $M$ is divided by $9$?

Find the least number which when decreased by $11$ is divisible by $14, 15, 21, 32$ and $60$.

Two pipes of length $1.5\, m$ and $1.2\, m$ are to be cut into equal pieces without leaving any extra length of pipes. The greatest length of the pipe pieces of same size which can be cut from these two lengths will be (in $metre$)

Given: $\sqrt[3]{4}, \sqrt{3}, \sqrt[6]{25}$ and $\sqrt[12]{289},$ the greatest and least of them are respectively

Vedclass Test Series

Exam Paper Generator

Online Exam Module