What is the angular velocity of the second hand of a clock?

If the angular velocity of a merry-go-round is $60^o/s$ and you are $3.5\,m$ from the centre of rotation,your linear velocity will be

$A$ body is revolving with a uniform speed '$v$' in a circle of radius '$r$'. The tangential acceleration is:

The angular speed of the minute hand of a clock in degrees per second is

$A$ particle $P$ is moving in a circle of radius $a$ with a uniform speed $v$. $C$ is the centre of the circle and $AB$ is a diameter. When passing through $B$,the angular velocity of $P$ about $A$ and $C$ are in the ratio:

$A$ particle moving with uniform speed in a circular path maintains: