What is the chance that a leap year selected | vedclass

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(B) leap year has $366$ days,which consists of $52$ full weeks and $2$ additional days.The possible pairs for these $2$ extra days are:$\{(	ext{Sunda

Vedclass · Accepted Answer

$\frac{2}{7}$

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(B) leap year has $366$ days,which consists of $52$ full weeks and $2$ additional days.The possible pairs for these $2$ extra days are:$\{(	ext{Sunday, Monday}), (	ext{Monday, Tuesday}), (	ext{Tuesday, Wednesday}), (	ext{Wednesday, Thursday}), (	ext{Thursday, Friday}), (	ext{Friday, Saturday}), (	ext{Saturday, Sunday})\}$Therefore,the total number of outcomes is $n(S) = 7$.For the year to have $53$ Wednesdays,one of the two extra days must be a Wednesday. The favorable outcomes are:$\{(	ext{Tuesday, Wednesday}), (	ext{Wednesday, Thursday})\}$Thus,the number of favorable outcomes is $n(E) = 2$.The probability $P(E)$ is given by $\frac{n(E)}{n(S)} = \frac{2}{7}$.

What is the chance that a leap year selected randomly will have $53$ Wednesdays?

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