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(D) The salts $Na_2O$,$Na_2S$,$Na_2Se$,and $Na_2Te$ undergo anionic hydrolysis in water to form $NaOH$ and the corresponding weak acid ($H_2O$,$H_2S$,

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$pH_1 > pH_2 > pH_3 > pH_4$

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(D) The salts $Na_2O$,$Na_2S$,$Na_2Se$,and $Na_2Te$ undergo anionic hydrolysis in water to form $NaOH$ and the corresponding weak acid ($H_2O$,$H_2S$,$H_2Se$,$H_2Te$ respectively).The $pH$ of these solutions depends on the strength of the conjugate acid formed. The weaker the conjugate acid,the stronger the conjugate base,and the higher the $pH$ of the solution.The acidic strength order of the hydrides is $H_2O Therefore,the basic strength of the conjugate bases follows the order $OH^- > HS^- > HSe^- > HTe^-$.Consequently,the $pH$ values of their isomolar solutions follow the order $pH_1 > pH_2 > pH_3 > pH_4$.

What is the correct relationship between the $pH$ values of isomolar solutions of sodium oxide $(pH_1)$,sodium sulphide $(pH_2)$,sodium selenide $(pH_3)$,and sodium telluride $(pH_4)$?

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