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(D) The enamel of teeth is composed of hydroxyapatite,which has the formula $Ca_{10}(PO_4)_6(OH)_2$. When it reacts with $F^{-}$ ions,the $OH^{-}$ ion

Vedclass · Accepted Answer

$3[Ca_3(PO_4)_2 \cdot CaF_2]$

Vedclass · Answer

(D) The enamel of teeth is composed of hydroxyapatite,which has the formula $Ca_{10}(PO_4)_6(OH)_2$. When it reacts with $F^{-}$ ions,the $OH^{-}$ ions are replaced by $F^{-}$ ions to form fluorapatite: $Ca_{10}(PO_4)_6(OH)_2 + 2 F^{-} \longrightarrow Ca_{10}(PO_4)_6 F_2 + 2 OH^{-}$ This product,$Ca_{10}(PO_4)_6 F_2$,can be represented as $3[Ca_3(PO_4)_2] \cdot CaF_2$. Therefore,option $(D)$ is the correct answer.

What is the formula of the product formed when $F^{-}$ reacts with enamel on teeth?

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