What is the molarity of an H_2SO_4 solution t | vedclass

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(C) Given: $98 \ \%$ $H_2SO_4$ by weight means $98 \ g$ of $H_2SO_4$ is present in $100 \ g$ of the solution.Step $1$: Calculate the volume of the sol

Vedclass · Accepted Answer

$18.4$

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(C) Given: $98 \ \%$ $H_2SO_4$ by weight means $98 \ g$ of $H_2SO_4$ is present in $100 \ g$ of the solution.Step $1$: Calculate the volume of the solution.$Volume = \frac{Mass}{Density} = \frac{100 \ g}{1.84 \ g/cc} \approx 54.35 \ cc = 0.05435 \ L$.Step $2$: Calculate the moles of solute $(H_2SO_4)$.Molar mass of $H_2SO_4 = 2(1) + 32 + 4(16) = 98 \ g/mol$.Moles of $H_2SO_4 = \frac{98 \ g}{98 \ g/mol} = 1 \ mol$.Step $3$: Calculate Molarity $(M)$.$M = \frac{	ext{Moles of solute}}{	ext{Volume of solution in } L} = \frac{1 \ mol}{0.05435 \ L} \approx 18.4 \ M$.

What is the molarity of an $H_2SO_4$ solution that has a density of $1.84 \ g/cc$ at $35 \ ^oC$ and contains $98 \ \%$ solute by weight?

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