What is the number of atoms present in 2.24 | vedclass

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(B) At $STP$,$22.4 \ dm^3$ of any gas contains $1 \ mol$ of molecules.$1 \ mol$ of $NH_3$ contains $6.022 	imes 10^{23}$ molecules.Each $NH_3$ molecu

Vedclass · Accepted Answer

$2.4088 	imes 10^{23}$

Vedclass · Answer

(B) At $STP$,$22.4 \ dm^3$ of any gas contains $1 \ mol$ of molecules.$1 \ mol$ of $NH_3$ contains $6.022 	imes 10^{23}$ molecules.Each $NH_3$ molecule contains $4$ atoms $(1 \ N + 3 \ H)$.Therefore,$1 \ mol$ of $NH_3$ contains $4 	imes 6.022 	imes 10^{23} = 2.4088 	imes 10^{24}$ atoms.Given volume $= 2.24 \ dm^3$,which is $0.1 \ mol$ of $NH_3$.Number of atoms $= 0.1 	imes 2.4088 	imes 10^{24} = 2.4088 	imes 10^{23}$ atoms.

What is the number of atoms present in $2.24 \ dm^3$ of $NH_3$ $(g)$ at $STP$?

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