What is the number of electrons present in th | vedclass

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(B) The atomic number $27$ corresponds to Cobalt $(Co)$.The electronic configuration of neutral $Co$ $(Z=27)$ is $[Ar] \ 3d^7 \ 4s^2$.When $Co$ is in

Vedclass · Accepted Answer

$7$

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(B) The atomic number $27$ corresponds to Cobalt $(Co)$.The electronic configuration of neutral $Co$ $(Z=27)$ is $[Ar] \ 3d^7 \ 4s^2$.When $Co$ is in the $+2$ oxidation state,it loses two electrons from the $4s$ orbital.The resulting electronic configuration is $[Ar] \ 3d^7$.Therefore,the number of electrons in the $d$-subshell is $7$.

What is the number of electrons present in the $d$-subshell if the atomic number is $27$ and the oxidation state is $+2$?

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