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The oxidation number of sulphur in $S_8$ molecule is

Which ordering of compounds is according to the decreasing order of the oxidation state of nitrogen?

The oxidation number of sulphur in $H_2SO_4$ is

The oxidation states of $S$ in $H_2S_2O_7$ are:

$A$ compound contains atoms of three elements $A$,$B$ and $C$. If the oxidation number of $A$ is $+2$,$B$ is $+5$ and that of $C$ is $-2$,the possible formula of the compound is:

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