(B) In $7B$ $(OsO_4)$,the oxidation state of $Os$ is calculated as: $x + 4(-2) = 0$,so $x = +8$. In $7C$,the osmium atom is bonded to two oxygen atoms

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(B) In $7B$ $(OsO_4)$,the oxidation state of $Os$ is calculated as: $x + 4(-2) = 0$,so $x = +8$. In $7C$,the osmium atom is bonded to two oxygen atoms via single bonds (from the cyclic ester linkage) and two oxygen atoms via double bonds. The oxidation state is calculated as: $x + 2(-1) + 2(-2) = 0$,which gives $x - 2 - 4 = 0$,so $x = +6$.