What is the product Z in the following reacti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The first step is the Sandmeyer reaction where benzene diazonium chloride $(C_6H_5N_2Cl)$ reacts with $Cu_2Cl_2/HCl$ to form chlorobenzene $(

Vedclass · Accepted Answer

$p$-Chlorotoluene

Vedclass · Answer

(B) $1$. The first step is the Sandmeyer reaction where benzene diazonium chloride $(C_6H_5N_2Cl)$ reacts with $Cu_2Cl_2/HCl$ to form chlorobenzene $(X = C_6H_5Cl)$.$2$. The second step is the Wurtz-Fittig reaction where chlorobenzene reacts with methyl chloride $(CH_3Cl)$ and sodium $(Na)$ in dry ether to form toluene $(Y = C_6H_5CH_3)$.$3$. The third step is electrophilic aromatic substitution (chlorination) of toluene using $Cl_2$ in the presence of $Fe$ (a Lewis acid catalyst) in the dark. Since the methyl group $(-CH_3)$ is ortho/para directing,the major product formed is $p$-chlorotoluene $(Z = p-Cl-C_6H_4-CH_3)$.

What is the product $Z$ in the following reaction sequence?
$C_6H_5N_2Cl$ $\xrightarrow{Cu_2Cl_2/HCl} X$ $\xrightarrow{CH_3Cl/Na, \text{dry ether}} Y$ $\xrightarrow{Cl_2/Fe, \text{dark}} Z$

Similar Questions

Heating chlorobenzene with $NaOH$ at $300\,^oC$ under pressure yields ...........

Chlorobenzene reacts with bromine gas in the presence of $Anhyd. AlBr_3$ to yield $p-$Bromochlorobenzene. This reaction is classified as . . . . . .

Identify the product formed from chlorobenzene on heating with conc. $HNO_3$ in the presence of conc. $H_2SO_4$.

What is the ratio of $sp^3$ carbons to $sp^2$ carbons in the product '$P$' of the given sequence of reactions?

Chlorobenzene reacts with trichloroacetaldehyde (chloral) in the presence of $H_2SO_4$.
$2 C_6H_5Cl + CCl_3CHO \xrightarrow{H_2SO_4} \text{Major Product}$
The major product formed is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the product $Z$ in the following reaction sequence?$C_6H_5N_2Cl$ $\xrightarrow{Cu_2Cl_2/HCl} X$ $\xrightarrow{CH_3Cl/Na, \text{dry ether}} Y$ $\xrightarrow{Cl_2/Fe, \text{dark}} Z$