What is the ratio of sp^3 carbons to sp^2 car | vedclass

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(D) The starting material is chlorobenzene. Friedel-Crafts acylation with $CH_3COCl$ in the presence of anhydrous $AlCl_3$ gives $p$-chloroacetophenon

Vedclass · Accepted Answer

$1 : 3$

Vedclass · Answer

(D) The starting material is chlorobenzene. Friedel-Crafts acylation with $CH_3COCl$ in the presence of anhydrous $AlCl_3$ gives $p$-chloroacetophenone as the major product '$Q$' because the $-Cl$ group is ortho/para directing.$Q = p-Cl-C_6H_4-COCH_3$.Clemmensen reduction of '$Q$' using $Zn-Hg$ and $conc. HCl$ reduces the carbonyl group $(-COCH_3)$ to an ethyl group $(-CH_2CH_3)$.Thus,the final product '$P$' is $p$-chloroethylbenzene,which is $Cl-C_6H_4-CH_2CH_3$.In $p$-chloroethylbenzene $(C_8H_9Cl)$:- The carbons in the ethyl group are: $-CH_2-$ $(sp^3)$ and $-CH_3$ $(sp^3)$. Total $sp^3$ carbons = $2$.- The carbons in the benzene ring are all $sp^2$. Total $sp^2$ carbons = $6$.- The ratio of $sp^3$ carbons to $sp^2$ carbons = $2 : 6 = 1 : 3$.

What is the ratio of $sp^3$ carbons to $sp^2$ carbons in the product '$P$' of the given sequence of reactions?

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