What is the solubility of BaSO_4 in text{g/dm | vedclass

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(A) The dissociation of $BaSO_4$ is: $BaSO_4(s) ightleftharpoons Ba^{2+}(aq) + SO_4^{2-}(aq)$.Let solubility be $S 	ext{ mol/L}$. Then $K_{sp} = [B

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$2.33 	imes 10^{-3} 	ext{ g/dm}^3$

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(A) The dissociation of $BaSO_4$ is: $BaSO_4(s) ightleftharpoons Ba^{2+}(aq) + SO_4^{2-}(aq)$.Let solubility be $S 	ext{ mol/L}$. Then $K_{sp} = [Ba^{2+}][SO_4^{2-}] = S^2$.$S = \sqrt{K_{sp}} = \sqrt{1.0 	imes 10^{-10}} = 1.0 	imes 10^{-5} 	ext{ mol/L}$.Since $1 	ext{ mol/L} = 1 	ext{ mol/dm}^3$, $S = 1.0 	imes 10^{-5} 	ext{ mol/dm}^3$.Solubility in $	ext{g/dm}^3 = S 	imes 	ext{Molar mass} = 1.0 	imes 10^{-5} 	ext{ mol/dm}^3 	imes 233 	ext{ g/mol} = 2.33 	imes 10^{-3} 	ext{ g/dm}^3$.

What is the solubility of $BaSO_4$ in $\text{g/dm}^3$ if its solubility product is $1.0 \times 10^{-10}$ at $25^\circ\text{C}$? [Molar mass of $BaSO_4 = 233 \text{ g/mol}$]

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