What is the total number of electrons present | vedclass

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(C) The electronic configuration of $O_2$ molecule is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2

Vedclass · Accepted Answer

$10$

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(C) The electronic configuration of $O_2$ molecule is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^1 (\pi^* 2p_y)^1$. Bonding molecular orbitals are those without an asterisk $(*)$. These are $(\sigma 1s)^2$,$(\sigma 2s)^2$,$(\sigma 2p_z)^2$,$(\pi 2p_x)^2$,and $(\pi 2p_y)^2$. Total number of electrons in bonding orbitals = $2 + 2 + 2 + 2 + 2 = 10$.

What is the total number of electrons present in bonding orbitals of $O_2$ molecule according to molecular orbital theory?

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