What is the value of w (mass of solute in gra | vedclass

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(A) Normality $(N)$ is defined as the number of gram equivalents of solute per liter of solution.The formula for normality is: $N = \frac{	ext{Number

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$w = \frac{N \cdot E \cdot V}{1000}$

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(A) Normality $(N)$ is defined as the number of gram equivalents of solute per liter of solution.The formula for normality is: $N = \frac{	ext{Number of gram equivalents}}{	ext{Volume of solution in } L}$Number of gram equivalents = $\frac{w}{E}$,where $w$ is the mass of solute in grams and $E$ is the equivalent weight.Substituting this into the normality formula: $N = \frac{w}{E \cdot V(L)}$Since $V(L) = \frac{V(mL)}{1000}$,we get: $N = \frac{w \cdot 1000}{E \cdot V(mL)}$Rearranging for $w$: $w = \frac{N \cdot E \cdot V(mL)}{1000}$.

What is the value of $w$ (mass of solute in grams) required to prepare a definite volume of a standard solution of known normality $(N)$?
[$N = \text{normality}$,$E = \text{equivalent weight}$,$V = \text{volume of solution in } mL$]

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What is the value of $w$ (mass of solute in grams) required to prepare a definite volume of a standard solution of known normality $(N)$?[$N = \text{normality}$,$E = \text{equivalent weight}$,$V = \text{volume of solution in } mL$]