The composition of a sample of wustite is Fe_ | vedclass

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(B) Let the number of $Fe^{2+}$ ions be $x$ and the number of $Fe^{3+}$ ions be $y$. Given the total number of $Fe$ ions is $x + y = 0.93$. Since the

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$15$

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(B) Let the number of $Fe^{2+}$ ions be $x$ and the number of $Fe^{3+}$ ions be $y$. Given the total number of $Fe$ ions is $x + y = 0.93$. Since the compound is electrically neutral,the total positive charge must equal the total negative charge. $2x + 3y = 2$ (charge on $O^{2-}$ is $-2$). From the first equation,$x = 0.93 - y$. Substituting into the second equation: $2(0.93 - y) + 3y = 2$. $1.86 - 2y + 3y = 2$. $y = 2 - 1.86 = 0.14$. So,$x = 0.93 - 0.14 = 0.79$. The percentage of $Fe^{3+}$ ions is $\frac{y}{x+y} 	imes 100 = \frac{0.14}{0.93} 	imes 100 \approx 15.05\%$. Thus,the percentage is nearly $15\%$.

The composition of a sample of wustite is $Fe_{0.93} O_{1.00}$. The percentage of iron in the form of $Fe^{3+}$ ion is nearly:

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