What is the value of Delta H - Delta U for th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The relationship between $\Delta H$ and $\Delta U$ is given by the equation: $\Delta H = \Delta U + \Delta n_g RT$. Rearranging this,we get $\Delt

Vedclass · Accepted Answer

$-2 RT$

Vedclass · Answer

(D) The relationship between $\Delta H$ and $\Delta U$ is given by the equation: $\Delta H = \Delta U + \Delta n_g RT$. Rearranging this,we get $\Delta H - \Delta U = \Delta n_g RT$. For the reaction $2 C_{(s)} + 3 H_{2(g)} ightarrow C_2H_{6(g)}$,the change in the number of moles of gaseous species is $\Delta n_g = (n_{g, 	ext{products}}) - (n_{g, 	ext{reactants}})$. Here,$n_{g, 	ext{products}} = 1$ (for $C_2H_{6(g)}$) and $n_{g, 	ext{reactants}} = 3$ (for $H_{2(g)}$). Thus,$\Delta n_g = 1 - 3 = -2$. Substituting this value into the equation,we get $\Delta H - \Delta U = -2 RT$.

What is the value of $\Delta H - \Delta U$ for the following reaction? $2 C_{(s)} + 3 H_{2(g)} \rightarrow C_2H_{6(g)}$

Similar Questions

Which one of the following is an extensive property?

Extensive properties depend on the quantity of matter,while intensive properties do not. Classify the following properties as extensive or intensive:
Mass,internal energy,pressure,heat capacity,molar heat capacity,density,mole fraction,specific heat,temperature,and molarity.

What is the work done in $cal$ during the reversible isothermal expansion of $1 \, mol$ of an ideal gas at $300 \, K$ from $10 \, atm$ to $1 \, atm$?

In an endothermic reaction,the value of the change in enthalpy $(\Delta H)$ is

When $2$ moles of an ideal gas are expanded isothermally from a volume of $12.5 \ L$ to $15.0 \ L$ against a constant external pressure of $760 \ mm \ Hg$,calculate the amount of work done in joules. (in $J$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module