What is the volume of 1 mole of a crystalline | vedclass

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Question

(A) Edge length $a = 16 	imes 10^{-8} \ cm$. Volume of one unit cell $= a^{3} = (16 	imes 10^{-8} \ cm)^{3} = 4096 	imes 10^{-24} \ cm^{3}$. Since

Vedclass · Accepted Answer

$102.7 \ cm^{3} \ mol^{-1}$

Vedclass · Answer

(A) Edge length $a = 16 	imes 10^{-8} \ cm$. Volume of one unit cell $= a^{3} = (16 	imes 10^{-8} \ cm)^{3} = 4096 	imes 10^{-24} \ cm^{3}$. Since the unit cell contains $24$ molecules,the volume occupied by $24$ molecules is $4096 	imes 10^{-24} \ cm^{3}$. Volume of $1$ mole of molecules $= (	ext{Volume of } 24 	ext{ molecules} / 24) 	imes N_{A}$. Volume of $1$ mole $= (4096 	imes 10^{-24} / 24) 	imes 6.022 	imes 10^{23} \ cm^{3} \ mol^{-1}$. Volume of $1$ mole $\approx 170.67 	imes 10^{-24} 	imes 6.022 	imes 10^{23} \approx 102.77 \ cm^{3} \ mol^{-1}$.

What is the volume of $1$ mole of a crystalline solid having unit cell edge length $16 \times 10^{-8} \ cm$,if its unit cell contains $24$ molecules?

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