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(A) The reduction of chloroform $(CHCl_3)$ depends on the reagents used:$1$. $CHCl_3 + 2H \xrightarrow{Zn/HCl 	ext{ (alc.)}} CH_2Cl_2 + HCl$. The pro

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$CH_2Cl_2, CH_3Cl, CH_4$

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(A) The reduction of chloroform $(CHCl_3)$ depends on the reagents used:$1$. $CHCl_3 + 2H \xrightarrow{Zn/HCl 	ext{ (alc.)}} CH_2Cl_2 + HCl$. The product is dichloromethane $(CH_2Cl_2)$.$2$. $CHCl_3 + 4H \xrightarrow{Zn/HCl 	ext{ (aq.)}} CH_3Cl + 2HCl$. The product is chloromethane $(CH_3Cl)$.$3$. $CHCl_3 + 6H \xrightarrow{Zn/H_2O} CH_4 + 3HCl$. The product is methane $(CH_4)$.Thus,the sequence of products is $CH_2Cl_2, CH_3Cl, CH_4$.

What will be the reduction products of the following reactions:
$CHCl_3 \xrightarrow[Zn/HCl \text{ (alc.)}]{+2H}$
$CHCl_3 \xrightarrow[Zn/HCl \text{ (aq.)}]{+4H}$
$CHCl_3 \xrightarrow[Zn/H_2O]{+6H}$

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What will be the reduction products of the following reactions:$CHCl_3 \xrightarrow[Zn/HCl \text{ (alc.)}]{+2H}$$CHCl_3 \xrightarrow[Zn/HCl \text{ (aq.)}]{+4H}$$CHCl_3 \xrightarrow[Zn/H_2O]{+6H}$