What will be the volume of CO_2 at NTP obtain | vedclass

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(B) The chemical equation for the decomposition of limestone $(CaCO_3)$ is:$CaCO_3(s) 	o CaO(s) + CO_2(g)$$1$. Calculate the mass of pure $CaCO_3$:$M

Vedclass · Accepted Answer

$2.016$

Vedclass · Answer

(B) The chemical equation for the decomposition of limestone $(CaCO_3)$ is:$CaCO_3(s) 	o CaO(s) + CO_2(g)$$1$. Calculate the mass of pure $CaCO_3$:$Mass = 10 \ g 	imes 0.90 = 9 \ g$$2$. Calculate the moles of $CaCO_3$:Molar mass of $CaCO_3 = 40 + 12 + (3 	imes 16) = 100 \ g/mol$$Moles = \frac{9 \ g}{100 \ g/mol} = 0.09 \ mol$$3$. According to the stoichiometry,$1 \ mol$ of $CaCO_3$ produces $1 \ mol$ of $CO_2$ at $NTP$ $(22.4 \ L)$:$Volume = 0.09 \ mol 	imes 22.4 \ L/mol = 2.016 \ L$

What will be the volume of $CO_2$ at $NTP$ obtained on heating $10 \ g$ of ($90\%$ pure) limestone (in $L$)?

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