What would be the IUPAC name and symbol for t | vedclass

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Question

(A) The $IUPAC$ nomenclature for elements with atomic number $> 100$ uses specific roots for digits: $0 = nil$,$1 = un$,$2 = bi$.
For atomic numbe

Vedclass · Accepted Answer

Unbinilium,$Ubn$

Vedclass · Answer

(A) The $IUPAC$ nomenclature for elements with atomic number $> 100$ uses specific roots for digits: $0 = nil$,$1 = un$,$2 = bi$.
For atomic number $120$,the roots are $un$ $(1)$,$bi$ $(2)$,and $nil$ $(0)$.
Combining these roots and adding the suffix $-ium$ gives the name $Unbinilium$.
The symbol is derived from the first letters of the roots: $U$ $(un)$,$b$ $(bi)$,and $n$ $(nil)$,resulting in $Ubn$.

	
		
			$Digit$
			$Name-Abbreviation$
		
		
			$0$
			$nil-n$
		
		
			$1$
			$un-u$
		
		
			$2$
			$bi-b$

Temporary Systematic Name	$IUPAC$ Official Name
$a$. Unnilunium $(101)$	$i$. Mendelevium $(Md)$
$b$. Unniltrium $(103)$	$ii$. Lawrencium $(Lr)$
$c$. Unnilhexium $(106)$	$iii$. Seaborgium $(Sg)$
$d$. Ununnilium $(110)$	$iv$. Darmstadtium $(Ds)$

What would be the $IUPAC$ name and symbol for the element with atomic number $120$?

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The element with atomic number $12$ belongs to ......... group and ......... period.

Identify the incorrect match :

Temporary Systematic Name $IUPAC$ Official Name

$a$. Unnilunium $(101)$ $i$. Mendelevium $(Md)$

$b$. Unniltrium $(103)$ $ii$. Lawrencium $(Lr)$

$c$. Unnilhexium $(106)$ $iii$. Seaborgium $(Sg)$

$d$. Ununnilium $(110)$ $iv$. Darmstadtium $(Ds)$

The last member in each period of the periodic table is

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