When (P) undergoes Hoffmann exhaustive methyl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The starting material $(P)$ is morpholine. $1$. First,exhaustive methylation of the secondary amine $(P)$ with excess $CH_3I$ followed by treatmen

Vedclass · Accepted Answer

Divinyl ether

Vedclass · Answer

(A) The starting material $(P)$ is morpholine. $1$. First,exhaustive methylation of the secondary amine $(P)$ with excess $CH_3I$ followed by treatment with $Ag_2O/H_2O$ and heat (Hofmann elimination) leads to the ring opening and formation of an intermediate. $2$. The second round of exhaustive methylation and elimination removes the nitrogen group entirely. $3$. The final product obtained is divinyl ether,which has the structure $CH_2=CH-O-CH=CH_2$.

When $(P)$ undergoes Hoffmann exhaustive methylation (twice) then the product obtained will be

Similar Questions

Identify the major product from the following reaction sequence.

$R-NH-CHO \xrightarrow[\text{pyridine}]{POCl_3} \text{ product}$
In the given reaction,what will be the product?

What is the correct order of basic strength for $NH_3$,$CH_3NH_2$,and $(CH_3)_2NH$?

Which of the following substances will have the lowest boiling point?

Identify $X$ and $Y$ in the following reaction: ${C_6H_5NH_2}$ $\xrightarrow[0^{\circ} - 5^{\circ}C]{NaNO_2 + 2HCl} X$ $\xrightarrow[H_2O]{HNO_2} Y + N_2 + HCl$

Vedclass Test Series

Exam Paper Generator

Online Exam Module