When 0.1 , m CH_3COOH is present in a solvent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The elevation in boiling point is given by $\Delta T_b = i K_b m$. Given $\Delta T_b = 0.75 \, ^oC$,$K_b = 5 \, K \, kg \, mol^{-1}$,and $m = 0.1

Vedclass · Accepted Answer

$5 	imes 10^{-2}$

Vedclass · Answer

(A) The elevation in boiling point is given by $\Delta T_b = i K_b m$. Given $\Delta T_b = 0.75 \, ^oC$,$K_b = 5 \, K \, kg \, mol^{-1}$,and $m = 0.1 \, m$. Substituting these values: $0.75 = i 	imes 5 	imes 0.1$. $i = \frac{0.75}{0.5} = 1.5$. For the dissociation of $CH_3COOH ightleftharpoons CH_3COO^- + H^+$,the van't Hoff factor $i = 1 + \alpha$. $1.5 = 1 + \alpha \implies \alpha = 0.5$. The dissociation constant $K_a$ is given by $K_a = \frac{c \alpha^2}{1 - \alpha}$. $K_a = \frac{0.1 	imes (0.5)^2}{1 - 0.5} = \frac{0.1 	imes 0.25}{0.5} = 0.05 = 5 	imes 10^{-2}$.

When $0.1 \, m$ $CH_3COOH$ is present in a solvent,it shows an elevation in boiling point of $0.75 \, ^oC$. The acid dissociation constant $(K_a)$ will be: (Given: $K_b = 5 \, K \, kg \, mol^{-1}$)

Similar Questions

Identify the false statement from the following.

What type of solution is iodine in air?

Pick the correct statement.

Benzene and naphthalene form an ideal solution at room temperature. For this process,the true statement$(s)$ is (are)
$(A)$ $\Delta G$ is positive
$(B)$ $\Delta S_{\text{system}}$ is positive
$(C)$ $\Delta S_{\text{surroundings}} = 0$
$(D)$ $\Delta H = 0$

Vedclass Test Series

Exam Paper Generator

Online Exam Module