When $80 \ J$ of heat is absorbed by a monoatomic gas,its volume increases by $16 \times 10^{-5} \ m^3$ at constant pressure. The pressure of the gas is

The ratio of work done by an ideal rigid diatomic gas to the heat supplied to the gas in an isobaric process is (in $/7$)

$0.08 \text{ kg}$ of air is heated at constant volume through $5^{\circ} \text{C}$. The specific heat of air at constant volume is $0.17 \text{ kcal/kg}^{\circ} \text{C}$ and $J = 4.18 \text{ J/cal}$. The change in its internal energy is approximately: (in $\text{ J}$)

In a thermodynamic isobaric process:

An ideal gas undergoes the process $1 \rightarrow 2$ as shown in the figure. The heat supplied and work done in the process are $\Delta Q$ and $\Delta W$ respectively. The ratio $\Delta Q : \Delta W$ is

An ideal monoatomic gas expands at constant pressure. The work done by the gas on its environment is $200 \,J$, then the heat absorbed by the gas during the process is (in $\,J$)