When a J-shaped conducting rod is rotating in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The induced electromotive force $(emf)$ across a rotating conducting rod in a uniform magnetic field is given by the formula $e = \frac{1}{2} B \o

Vedclass · Accepted Answer

$\frac{1}{2}B\omega(L^2 + l^2)$

Vedclass · Answer

(C) The induced electromotive force $(emf)$ across a rotating conducting rod in a uniform magnetic field is given by the formula $e = \frac{1}{2} B \omega r^2$,where $r$ is the perpendicular distance from the axis of rotation to the end of the rod.In this case,the rod is $J$-shaped,but the induced $emf$ depends only on the displacement vector between the two endpoints of the rod relative to the axis of rotation.The effective distance $r$ from the pivot point $P$ to the other end $Q$ is the straight-line distance between them. Based on the geometry of the rod,this distance is $r = \sqrt{l^2 + L^2}$.Substituting this into the formula,we get:$e = \frac{1}{2} B \omega (\sqrt{l^2 + L^2})^2$Simplifying the expression:$e = \frac{1}{2} B \omega (l^2 + L^2)$

When a $J$-shaped conducting rod is rotating in its own plane with constant angular velocity $\omega$,about one of its ends $P$,in a uniform magnetic field $\vec B$ (directed normally into the plane of the paper),then the magnitude of the emf induced across it will be:

Similar Questions

Given that $K_w$ for water is $10^{-13} \ M^2$ at $62 \ ^oC$,compute the sum of $pOH$ and $pH$ for a neutral aqueous solution at $62 \ ^oC$.

If the volume of a block of metal changes by $0.12 \%$ when it is heated through $20 ^oC$, the coefficient of linear expansion (in $^oC^{-1}$) of the metal is

Which organ receives only oxygenated blood?

What is the correct order of spin only magnetic moment (in $BM$) of $Mn^{2+}, Cr^{2+}$ and $V^{2+}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module