When a balanced die is rolled,the probability | vedclass

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(C) The total number of possible outcomes when a balanced die is rolled is $6$,which are $\{1, 2, 3, 4, 5, 6\}$.Let $E$ be the event of getting a numb

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$\frac{1}{3}$

Vedclass · Answer

(C) The total number of possible outcomes when a balanced die is rolled is $6$,which are $\{1, 2, 3, 4, 5, 6\}$.Let $E$ be the event of getting a number greater than $4$.The numbers greater than $4$ on a die are $5$ and $6$.Thus,the number of favorable outcomes is $2$.The probability $P(E)$ is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.$P(E) = \frac{2}{6} = \frac{1}{3}$.

When a balanced die is rolled,the probability of getting a number greater than $4$ on it is ..........

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