When a light of wavelength 'lambda' falls on | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) आइंस्टीन के प्रकाश-विद्युत समीकरण के अनुसार: $K_{max} = \frac{1}{2}mV^2 = \frac{hc}{\lambda} - \phi$, जहाँ $\phi$ कार्य फलन है।प्रथम स्थिति में: $

Vedclass · Accepted Answer

greater than $V(1.5)^{1/2}$

Vedclass · Answer

(B) आइंस्टीन के प्रकाश-विद्युत समीकरण के अनुसार: $K_{max} = \frac{1}{2}mV^2 = \frac{hc}{\lambda} - \phi$, जहाँ $\phi$ कार्य फलन है।प्रथम स्थिति में: $\frac{1}{2}mV^2 = \frac{hc}{\lambda} - \phi$ ... $(1)$दूसरी स्थिति में, नई तरंगदैर्ध्य $\lambda' = \frac{2\lambda}{3}$ है। मान लीजिए नई अधिकतम गति $V'$ है।$\frac{1}{2}m(V')^2 = \frac{hc}{2\lambda/3} - \phi = \frac{3hc}{2\lambda} - \phi = 1.5 \frac{hc}{\lambda} - \phi$समीकरण $(1)$ से, $\frac{hc}{\lambda} = \frac{1}{2}mV^2 + \phi$अतः, $\frac{1}{2}m(V')^2 = 1.5(\frac{1}{2}mV^2 + \phi) - \phi = 0.75mV^2 + 1.5\phi - \phi = 0.75mV^2 + 0.5\phi$$\frac{1}{2}m(V')^2 = 0.75mV^2 + 0.5\phi$$(V')^2 = 1.5V^2 + \frac{\phi}{m}$$(V')^2 > 1.5V^2$$V' > V(1.5)^{1/2}$अतः, नई अधिकतम गति $V(1.5)^{1/2}$ से अधिक होगी।

When a light of wavelength '$\lambda$' falls on the emitter of a photosensitive surface, the maximum speed of emitted photoelectrons is '$V$'. If the incident wavelength is changed to '$2\lambda/3$',the maximum speed of emitted photoelectrons will be

Similar Questions

The graph of stopping potential $(V_{s})$ against frequency $(\nu)$ of incident radiation is plotted for two different metals '$P$' and '$Q$' as shown in the graph. If $\phi_{P}$ and $\phi_{Q}$ are the work functions of metals '$P$' and '$Q$' respectively,then which of the following is correct?

$A$ metallic surface is illuminated with radiation of wavelength $\lambda$,the stopping potential is $V_0$. If the same surface is illuminated with radiation of wavelength $2 \lambda$,the stopping potential becomes $\frac{V_0}{4}$. The threshold wavelength for this metallic surface will be -

Light of wavelength '$\lambda$' which is less than threshold wavelength is incident on a photosensitive material. If incident wavelength is decreased so that emitted photoelectrons are moving with some velocity, then the stopping potential:

The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength $491\, nm$ is $0.710\, V$. When the incident wavelength is changed to a new value,the stopping potential is $1.43\, V$. The new wavelength is ....... $nm.$

Vedclass Test Series

Exam Paper Generator

Online Exam Module