When a number is divided by 56, the remainder | vedclass

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(C) Let the number be $N.$ According to the problem,when $N$ is divided by $56,$ the remainder is $29.$This can be expressed as $N = 56k + 29,$ where

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) Let the number be $N.$ According to the problem,when $N$ is divided by $56,$ the remainder is $29.$This can be expressed as $N = 56k + 29,$ where $k$ is an integer.We want to find the remainder when $N$ is divided by $8.$Substitute $N$ in the expression: $N = 8(7k) + 29.$Now,divide $29$ by $8$ to find the remainder: $29 = 8 	imes 3 + 5.$Therefore,$N = 8(7k) + 8(3) + 5 = 8(7k + 3) + 5.$When $N$ is divided by $8,$ the remainder is $5.$

When a number is divided by $56,$ the remainder is $29.$ If the same number is divided by $8,$ then the remainder will be:

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