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(D) The magnetic flux density $B$ inside a material is given by $B = \mu H$,where $\mu$ is the absolute permeability and $H$ is the magnetic field int

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$4$

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(D) The magnetic flux density $B$ inside a material is given by $B = \mu H$,where $\mu$ is the absolute permeability and $H$ is the magnetic field intensity.The flux density away from the piece (in vacuum or air) is $B_0 = \mu_0 H$.Given that the flux density inside the material is four times the flux density outside,we have $B = 4 B_0$.Substituting the expressions,we get $\mu H = 4 \mu_0 H$.Dividing both sides by $\mu_0 H$,we find the relative permeability $\mu_r = \frac{\mu}{\mu_0} = 4$.

When a piece of a ferromagnetic substance is placed in a uniform magnetic field,the flux density inside it is four times the flux density away from the piece. The magnetic permeability of the material is

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