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(D) For an equilateral prism,the prism angle $A = 60^o$. When a light ray is incident normally on one surface,the angle of incidence at the first surf

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The ray undergoes total internal reflection at the second refracting surface

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(D) For an equilateral prism,the prism angle $A = 60^o$. When a light ray is incident normally on one surface,the angle of incidence at the first surface is $0^o$,so the angle of refraction is also $0^o$. The ray travels straight and strikes the second surface at an angle of incidence $i = A = 60^o$.The critical angle $C$ for the material of the prism with refractive index $\mu = 1.5$ is given by:$C = \sin^{-1}(1/\mu) = \sin^{-1}(1/1.5) = \sin^{-1}(2/3) \approx 41.8^o$.Since the angle of incidence at the second surface $(i = 60^o)$ is greater than the critical angle $(C \approx 41.8^o)$,the condition for total internal reflection is satisfied.Therefore,the ray undergoes total internal reflection at the second refracting surface.

When a ray of light is incident normally on one refracting surface of an equilateral prism (Refractive index of the material of the prism $= 1.5$),what happens to the ray at the second refracting surface?

Similar Questions

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Angle of deviation $(\delta)$ by a prism (refractive index = $\mu$ and supposing the angle of prism $A$ to be small) can be given by

The figure shows the graph of the angle of deviation $\delta$ versus the angle of incidence $i$ for a light ray striking a prism. The prism angle $A$ is: (in $^{\circ}$)

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