When a system is taken from state i to a stat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The change in internal energy $\Delta U$ is a state function,meaning it depends only on the initial and final states,not on the path taken.For the

Vedclass · Accepted Answer

$-43$

Vedclass · Answer

(D) The change in internal energy $\Delta U$ is a state function,meaning it depends only on the initial and final states,not on the path taken.For the path $iaf$,the first law of thermodynamics is given by $\Delta Q = \Delta U + \Delta W$.Given $\Delta Q_{iaf} = 50 \, J$ and $\Delta W_{iaf} = 20 \, J$,we have:$\Delta U_{if} = \Delta Q_{iaf} - \Delta W_{iaf} = 50 \, J - 20 \, J = 30 \, J$.For the return path $fi$,the initial state is $f$ and the final state is $i$. Therefore,the change in internal energy is $\Delta U_{fi} = -\Delta U_{if} = -30 \, J$.Using the first law of thermodynamics for the path $fi$:$\Delta Q_{fi} = \Delta U_{fi} + \Delta W_{fi}$.Given $\Delta W_{fi} = -13 \, J$ and $\Delta U_{fi} = -30 \, J$,we get:$\Delta Q_{fi} = -30 \, J + (-13 \, J) = -43 \, J$.

When a system is taken from state $i$ to a state $f$ along path $iaf$,$Q = 50 \, J$ and $W = 20 \, J$. Along path $ibf$,$Q = 35 \, J$. If $W = -13 \, J$ for the curved return path $fi$,$Q$ for this path is ...... $J$.

Similar Questions

Which of the following laws of thermodynamics defines the term internal energy?

If $\Delta Q$ and $\Delta W$ represent the heat supplied to the system and the work done on the system respectively,then the first law of thermodynamics can be written as,where $\Delta U$ is the change in internal energy.

During the melting of a slab of ice at $273 \ K$ at atmospheric pressure,

Is it possible to convert internal energy into work or mechanical energy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module