When a wire loop is rotated in a magnetic field,the direction of induced $emf$ changes in every

  • A
    one revolution
  • B
    $1/2$ revolution
  • C
    $1/4$ revolution
  • D
    $2$ revolutions

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The number of turns in the coil of an $AC$ generator are $50$ and its cross-sectional area is $2.5 \ m^2$. This coil is revolving in a uniform magnetic field of strength $0.3 \ T$ with a uniform angular velocity of $60 \ rad \ s^{-1}$. The resistance of the circuit comprising the coil is $500 \ \Omega$. The maximum induced $emf$ and maximum current produced in the generator are:

The $e.m.f.$ induced in a coil of wire,which is rotating in a magnetic field,does not depend on

$A$ student pedals a stationary bicycle. The pedals of the bicycle are attached to a $100$ turn coil of area $0.10$ $m^2$. The coil rotates at half a revolution per second and it is placed in a uniform magnetic field of $0.01$ $T$ perpendicular to the axis of rotation of the coil. What is the maximum voltage generated in the coil (in $V$)?

In an $AC$ generator,a rectangular coil of $100$ turns each having area $14 \times 10^{-2} \, m^2$ is rotated at $360 \, rev/min$ about an axis perpendicular to a uniform magnetic field of magnitude $3.0 \, T$. The maximum value of the emf produced will be $............ \, V$. (Take $\pi = \frac{22}{7}$)

$A$ circular coil of area $0.01 \ m^2$ and $40$ turns is rotated about its vertical diameter with an angular speed of $50 \ rad \ s^{-1}$ in a uniform horizontal magnetic field of $0.05 \ T$. If the average power loss due to Joule heating is $25 \ mW$,then the closed loop resistance of the coil is: (in $\Omega$)

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