When an inorganic compound reacts with SO_2 i | vedclass

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(D) The reaction sequence is as follows:$1$. An inorganic compound (like $Ca(OH)_2$) reacts with $SO_2$ to form $(A)$ $(CaSO_3)$.$2$. $(A)$ $(CaSO_3)$

Vedclass · Accepted Answer

$Na_2S_2O_3$

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(D) The reaction sequence is as follows:$1$. An inorganic compound (like $Ca(OH)_2$) reacts with $SO_2$ to form $(A)$ $(CaSO_3)$.$2$. $(A)$ $(CaSO_3)$ reacts with $Na_2CO_3$ to give $(B)$ $(Na_2SO_3)$.$3$. Alternatively,the standard industrial process for preparing sodium thiosulphate involves: $2NaOH + SO_2 \rightarrow Na_2SO_3 + H_2O$.$4$. Then,$Na_2SO_3 + S \rightarrow Na_2S_2O_3$ (Compound $(C)$).$5$. $Na_2S_2O_3$ (Sodium thiosulphate) is widely used in photography as a fixing agent (hypo solution).

List-$I$	List-$II$
$(a) \ [S_2 O_3]^{2-}$	$(I)$ Paramagnetic
$(b) \ H_2 O_2$	$(II)$ Toxic gas
$(c) \ H_2 S$	$(III)$ Strong reducing agent
$(d) \ S_2$	$(IV)$ Disproportionate in presence of $Mn^{2+}$

When an inorganic compound reacts with $SO_2$ in an aqueous medium,it produces $(A)$. $(A)$ on reaction with $Na_2CO_3$ gives compound $(B)$,which with sulphur,gives a substance $(C)$ used in photography. Compound $(C)$ is:

Similar Questions

In which of the following arrangements is the given sequence not strictly according to the property indicated against it?

Assertion : Both rhombic and monoclinic sulphur exist as $S_8$ but oxygen exists as $O_2$.
Reason : Oxygen forms $p\pi-p\pi$ multiple bond due to small size and small bond length but $p\pi-p\pi$ bonding is not possible in sulphur.

Choose the $CORRECT$ statement.

Match the following items of List-$I$ with those in List-$II$ and choose the correct option.
List-$I$ List-$II$
$(a) \ [S_2 O_3]^{2-}$ $(I)$ Paramagnetic
$(b) \ H_2 O_2$ $(II)$ Toxic gas
$(c) \ H_2 S$ $(III)$ Strong reducing agent
$(d) \ S_2$ $(IV)$ Disproportionate in presence of $Mn^{2+}$

Oxygen is not evolved on reaction of ozone with

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