When compared to Delta G^{circ} for the forma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The stability of an oxide is determined by the magnitude of its standard Gibbs free energy of formation,$\Delta G^{\circ}$.$Al_{2}O_{3}$ is more s

Vedclass · Accepted Answer

higher

Vedclass · Answer

(A) The stability of an oxide is determined by the magnitude of its standard Gibbs free energy of formation,$\Delta G^{\circ}$.$Al_{2}O_{3}$ is more stable than $Cr_{2}O_{3}$,which means the $\Delta G^{\circ}$ value for the formation of $Al_{2}O_{3}$ is more negative (lower) than that of $Cr_{2}O_{3}$.Therefore,the $\Delta G^{\circ}$ for the formation of $Cr_{2}O_{3}$ is higher than that of $Al_{2}O_{3}$.

When compared to $\Delta G^{\circ}$ for the formation of $Al_{2}O_{3}$,the $\Delta G^{\circ}$ for the formation of $Cr_{2}O_{3}$ is

Similar Questions

Which one is used as a by-product in Serpeck's process?

$I$. $FeCr_2O_4 + NaOH + \text{air} \rightarrow Na_2CrO_4 + Fe_2O_3$
$II$. $Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7$
$Na_2CrO_4$ and $Fe_2O_3$ are separated by:

Describe the process of obtaining blister copper.

Who studied the plots of $\Delta G$ versus $T$?

In a blast furnace,the temperature of the hearth is maintained by which type of zone?

Vedclass Test Series

Exam Paper Generator

Online Exam Module