When the current in a coil changes from 8 ; A | vedclass

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(D) The induced $e.m.f.$ in a coil is given by the formula: $e = -L \frac{di}{dt}$.Here,the change in current $di = 2 \; A - 8 \; A = -6 \; A$.The tim

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$10$

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(D) The induced $e.m.f.$ in a coil is given by the formula: $e = -L \frac{di}{dt}$.Here,the change in current $di = 2 \; A - 8 \; A = -6 \; A$.The time interval $dt = 3 	imes 10^{-2} \; s$.The induced $e.m.f.$ $e = 2 \; V$.Substituting these values into the formula:$2 = -L \left( \frac{-6}{3 	imes 10^{-2}} ight)$.$2 = L \left( \frac{6}{3 	imes 10^{-2}} ight)$.$2 = L 	imes 200$.$L = \frac{2}{200} = 0.01 \; H$.Since $1 \; H = 1000 \; mH$,we have $L = 0.01 	imes 1000 = 10 \; mH$.

When the current in a coil changes from $8 \; A$ to $2 \; A$ in $3 \times 10^{-2} \; s$,the $e.m.f.$ induced in the coil is $2 \; V$. The self-inductance of the coil (in $mH$) is:

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