When the following aldohexose exists in its D | vedclass

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(C) The given structure is an aldohexose with three chiral centers at $C-3, C-4,$ and $C-5$. When it forms a pyranose ring,the $C-1$ carbon (the carbo

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$8$

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(C) The given structure is an aldohexose with three chiral centers at $C-3, C-4,$ and $C-5$. When it forms a pyranose ring,the $C-1$ carbon (the carbonyl carbon) becomes a new chiral center (anomeric carbon). Therefore,the total number of chiral centers in the pyranose form is $3 + 1 = 4$. The total number of stereoisomers is $2^n$,where $n$ is the number of chiral centers. Thus,the total number of stereoisomers $= 2^4 = 16$. However,the question specifies the $D$-configuration,which fixes the configuration at the highest numbered chiral center $(C-5)$. With the $D$-configuration fixed,the number of stereoisomers is $2^{n-1} = 2^{4-1} = 2^3 = 8$.

List-$I$ $(\text{Saccharides})$	List-$II$ $(\text{Glycosidic linkages found})$
$(A)$ Sucrose	$(I)$ $\alpha 1-4$
$(B)$ Maltose	$(II)$ $\alpha 1-4$ and $\alpha 1-6$
$(C)$ Lactose	$(III)$ $\alpha 1-\beta 2$
$(D)$ Amylopectin	$(IV)$ $\beta 1-4$

When the following aldohexose exists in its $D$-configuration,the total number of stereoisomers in its pyranose form is :
$CHO-CH_2-CH(OH)-CH(OH)-CH(OH)-CH_2OH$

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When the following aldohexose exists in its $D$-configuration,the total number of stereoisomers in its pyranose form is : $CHO-CH_2-CH(OH)-CH(OH)-CH(OH)-CH_2OH$